how to create 2 matrices from 1 matrix depending on values 0 & 1, displayed in first column of 1st matrix?

I have a matrix like this

A = [1 | 3 4 5 6 7 8 9;
     0 | 4 5 6 9 1 4 6;
     1 | 3 1 5 1 7 1 9;
     0 | 6 5 6 1 1 4 1];

first column has values 0 & 1

I want to create new matrices from the index of first column i.e. for 1 above will be like

B = [3 4 5 6 7 8 9;
     3 1 5 1 7 1 9];

and for value 0

C = [4 5 6 9 1 4 6;
     6 5 6 1 1 4 1];

can some one please guide me how to achieve this in Matlab, been trying a lot to do but the C coding aspects are not helping me much.

Please some one? thanks!

Answer 1

[Matt Fig]

Now I think I see what you did. You probably did not realize that the | symbol evaluates to logical OR when someone copies and pastes your code.... So leave that out, it is just confusing...

A = [1 3 4 5 6 7 8 9; 
     0 4 5 6 9 1 4 6; 
     1 3 1 5 1 7 1 9; 
     0 6 5 6 1 1 4 1]

A_ones = A(A(:,1)==1,2:end) 
A_zeros = A(~A(:,1),2:end)

[zaxven]

have used '|' symbol to only differentiate as 1st column. but anyways thanks a ton matt!