polynomial evaluation for a simple curve.

1 vue (au cours des 30 derniers jours)
Paul Rogers
Paul Rogers le 30 Juin 2020
After I got the coefficent from the command:
p1=polyfit(x,y,4);
the p1 vector is:
p1 =
-35.4628 39.9257 -14.8278 1.6022 1.1031
the x vector is:
x=[0:0.001:0.4000]
Now, how do I write like this:
I don't need the polyval command.

Réponse acceptée

Paul Rogers
Paul Rogers le 1 Juil 2020
formula = ((x.^4)*-35.4628) + ((x.^3)*39.9257) + ((x.^2)*-14.8278) + ((x.^1)*1.6022) + ((x.^0)*1.1031);

Plus de réponses (0)

Catégories

En savoir plus sur Polynomials dans Help Center et File Exchange

Produits


Version

R2014b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by