compressing a code, help me

Any one knows how to compress this code as much as possible?

for VetorN = fix((20*sqrt(2).^(0:5)))
[row,col] = size(VetorN);
i = (1: col);

discSt.N = VetorN(i);
VN = VetorN; 
CD0 = VetorN *3;
if VetorN == 20
    CD01 = CD0;
elseif VetorN == 28
    CD02 = CD0;
elseif VetorN == 40
    CD03 = CD0;
elseif VetorN == 56
    CD04 = CD0;
else 
    CD05 = CD0;     
end
pause()
end
MCD0 = [CD01 CD02 CD03 CD04 CD05]

[madhan ravi]

Why do you use pause()?

[Cauli Vilela Ferreira]

because generate a plot after each pause

Answer 1

[madhan ravi]

VetorN = fix( (20 * sqrt(2) .^ (0 : 5) ) )
MD0 = VetorN * 3;
MD0(end - 1) = [ ]

[Cauli Vilela Ferreira]

However the 'foor loop' is required :C

[madhan ravi]

VetorN = fix( (20 * sqrt(2) .^ (0 : 5) ) );
MD0 = zeros(1, numel(VectorN);
for k = 1 : numel(VetorN)
MD0(k) = VetorN(k) * 3;
end
MD0(end - 1) = [ ]

[Cauli Vilela Ferreira]

How cant i add VetorN(1,5), i forgot to put in the code

for VetorN = fix((20*sqrt(2).^(0:5)))
[row,col] = size(VetorN);
i = (1: col);
discSt.N = VetorN(i);
VN = VetorN; 
CD0 = VetorN *3;
if VetorN == 20
    CD01 = CD0;
elseif VetorN == 28
    CD02 = CD0;
elseif VetorN == 40
    CD03 = CD0;
elseif VetorN == 56
    CD04 = CD0;
elseif VetorN== 80
    CD05 = CD0; 
else
    CD06 = CD0;     
end
pause()
end
MCD0 = [CD01 CD02 CD03 CD04 CD05 CD06]

[madhan ravi]

So remove the last line in my code ;)

Answer 2

[Image Analyst]

Not sure why it needs to be compressed as much as possible, but this will compress it as much as possible while giving the very same output:

MCD0=[60,84,120,168,339]

This assumes that after that you no longer need the component variables CD01, CD02, CD03, CD04, CD05, and CD06. If you still need those variables for some reason, then of course you'll need to compute them.