Integral calculation using matlab
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MINAS KOUROUMPLAKIS
le 4 Août 2020
Modifié(e) : Bruno Luong
le 4 Août 2020
Hello i wish to calculate the following integral
My difficulty stems from the absolute value which is "outside" of the integral with respect to θ
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Bruno Luong
le 4 Août 2020
Modifié(e) : Bruno Luong
le 4 Août 2020
Feel free to change these hyper-parameters
n = 3
k = 2*pi*rand()
integral(@(phi) arrayfun(@(phi) abs(integral(@(theta) exp(1i*k*cos(theta-phi)).*cos(n*theta), 0, 2*pi)).^2, phi), 0, 2*pi)
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Matt J
le 4 Août 2020
Modifié(e) : Matt J
le 4 Août 2020
My difficulty stems from the absolute value which is "outside" of the integral
Why is this a difficulty? Because it prevents you from using integral2()? Just apply integral() twice instead.
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Steven Lord
le 4 Août 2020
Write a function to compute the inner integral. This function should accept phi. One wrinkle here is that since the outer integral call is going to pass a vector of values into it as phi, your inner integral call will need to say that the function is ArrayValued.
Write a function that takes the absolute value of that inner integral function.
Write a function to compute the outer integral of the absolute value function.
If you try this and it doesn't work, show us the code you wrote and we may be able to offer some guidance.
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