How can write loop for this algorithm?

If i have A={1 1 2 2 3 3 3 4 4 8 9 10}

How can i run data from 1

after that i plus that data with 1

if data that i got is in A it will plus 1

if i not it will stop loop and show that outcome too

from my example it will stop at 4 and show 4 as a outcome

Answer 1

[Jan]

I'm not sure, because the question is not completely clear to me. Perhaps:

A = [1 1 2 2 3 3 3 4 4 8 9 10];
d = diff(A);
v = find(d > 1, 1, 'first');
if isempty(v)
    disp('Number not found')
else
    A(v)
end

[Sakdinon Nopparit]

thank you

let me give you another example

if A=[-0.8687 -0.8677 -0.8677 -0.8667 -0.2547]

and i start from the first data and keep adding 0.001 until it not found the data in this array

from my example it will adding 0.001 until -0.8657 and it will stop becuase -0.8657 is not in this array

after that show previous data

[Jan]

What exactly is "the previous data"? Please explain explicitly, which output you want.

A = [-0.8687 -0.8677 -0.8677 -0.8667 -0.2547]
d = diff(A);
%  d = [0.0010         0    0.0010    0.6120]

So do you search for the first number, which is greater than 0.001? Then use the already suggested code.