how to compare each element of matrix?

here...i taken some variable as t ,value is 4(t=4),and f is a 4x4 matrix.. f=[1 2 3 4; 2 3 4 5 ; 5 6 7 8 ; 1 2 3 5].. how to compare the each element of matrix with T?

Answer 1

[Andrei Bobrov]

t = 4;
f = [1 2 3 4; 2 3 4 5 ; 5 6 7 8 ; 1 2 3 5];

out = abs(f - t) < eps(100)

ADD

out = f;
out(f <= t) = -4;

[Dhines]

t=4;
f=[1 2 3 4; 2 3 4 5 ; 5 6 7 8 ; 1 2 3 5];
out = abs(f - t) < eps(100)
if (out>t)
    fh=t;
else
    fh=-4;
end

..for this code i getting always '-4'...can u justify it?

[Andrei Bobrov]

here out is logical array, only 1's and 0's ( true and false )

[Dhines]

ok sir..want to get all value in vector form 'fh'...that is in f matrix ,the first element 1 is compare to t, then i get -4 for 2 that also -4 mean while i want to get each output of compared value with t. how to construct fh?

[Andrei Bobrov]

see ADD part in my answer

[Dhines]

thank u sir..little bit doubt there in ur add part...when i get output form of fh the lowest value as represent -4 thats ok. but the greater value want to present as '4' ,there is print as only matrix value..please correct that one .

[Andrei Bobrov]

out = t*((f > t)*2-1)