Making combinations using random number generators

8 vues (au cours des 30 derniers jours)
Chris Dan
Chris Dan le 28 Août 2020
Hello,
I have this vector
x0 = [1;88;88;2;2;2;2;2;-88;2]
Right now I change the values in this vector manually making combinations, I am looking for a random number generator which will generate combinations of numbers on these 10 slots, like a combination of 10 numbers from 0 till infinity, numbers can be decimals or integers as well or a combination of both
x0 = [x1;x2;x3;x4;x5;x6;x7;x8;x9;x10]
Does anyone knows how it can be done?
I have to use this vector elsewhere in the code...
  2 commentaires
Rafael Hernandez-Walls
Rafael Hernandez-Walls le 28 Août 2020
In general, you can generate N random numbers in the interval (a,b) with the formula:
r = a + (b-a).*rand(N,1)
Chris Dan
Chris Dan le 28 Août 2020
Hi, how can i make it run in a loop, so at each iteration I get a new combination

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Rafael Hernandez-Walls
Rafael Hernandez-Walls le 29 Août 2020
N=input('give me number of random elements:');
a=input('lower limit of the numbers to generate:');
b=input('upper limit of the numbers to generate:');
M=input('How many arrangements do you want to generate ?:');
r=zeros(N,M);
for k=1:M
r(:,k)=a+(b-a)*rand(N,1);
end
  1 commentaire
Rafael Hernandez-Walls
Rafael Hernandez-Walls le 30 Août 2020
oops!!!!
N=input('give me number of random elements:');
a=input('lower limit of the numbers to generate:');
b=input('upper limit of the numbers to generate:');
M=input('How many arrangements do you want to generate ?:');
r=zeros(N,M);
r(:,1)=a+(b-a)*rand(N,1);
for k=2:M
a=randperm(N);
r(:,k)=r(a,1);
end

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Plus de réponses (1)

Steven Lord
Steven Lord le 28 Août 2020
If you want to draw with replacement use randi to generate numbers between 1 and the numel of the array you want to sample. Use those as linear indices into the array.
If you want to draw without replacement use randperm to generate the linear indices.

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