Hanning window Frequency Domain Graph
17 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello,
I have calculated the time domain of the hanning window through the formula.
But now I have to find the frequency domain by using fft and fft shift which i have calculated but I want to know is this graph correct or not?
M = 40;
n = -M / 2: M / 2;
window = 0.5 + 0.5 * cos (2 * pi * n / M);
figure;
plot (n, window);
L = length (window);
NFFT = 1024;
X1 = fftshift (fft (window, NFFT) / length (window));
Freq = (-NFFT / 2: NFFT / 2-1) / NFFT; % Frequency vector
figure;
plot (Freq, X1 (1: length (Freq)) / max (X1), 'r' );
0 commentaires
Réponse acceptée
Pratyush Roy
le 22 Sep 2020
The graph for frequency response is correct. In case you want to generate a plot for magnitude response in decibels, make the following changes to the code:
Y1 = X1 (1: length (Freq)) / max (X1);
mag_dB = 10*log10(Y1);
plot(Freq,mag_dB);
The following link to the documentation might be helpful ofr generating frequency response for Hanning window using the 'hann' function available in the Signal Processing Toolbox in MATLAB.
0 commentaires
Plus de réponses (1)
Leo Dokoza
le 7 Mar 2021
Modifié(e) : Leo Dokoza
le 7 Mar 2021
What does "M" stand for? Could you explain your code?
0 commentaires
Voir également
Catégories
En savoir plus sur Fourier Analysis and Filtering dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!