How to replace multiple values with the same value in a cell array?

I would like to replace multiple values with the same value in a cell array.

% retrieve a vector with logical values
index = contains(oversikt.Jernbanen, '395');
% find the indexes of the index vector where the logical values = 1
index2 = find(index == 1);

% replace all the values. / the error:  "Expected one output from a curly brace or dot indexing expression, but there were 12 results."
oversikt.Jernbanen{1,index2} = '0';

[Stephen23]

find is not required. Logical indexing is simpler and more efficient, you should just use index directly.

[iseinas]

when I do this my

index2 == index1

will the latter part work normally?

[Stephen23]

You don't need index2 at all, just use index.

[iseinas]

Okay thank you so much!

Answer 1

[Stephen23]

The RHS must be a scalar cell.

The LHS must use parentheses, because you are replacing cells (not accessing their contents).

oversikt.Jernbanen(1,index) = {'0'};

Remember:

• () parentheses refer to the cells themselves
• {} curly braces refer to the cell contents.

[iseinas]

Okay, I see. So parentheses are for replacing while {} these are for accessing cell contents am I right?

[madhan ravi]

oversikt.Jernbanen(1,index) = {'0'};

[Stephen23]

"... {} these are for accessing cell contents"

Correct.

"So parentheses are for replacing ..."

Parenthese are not just "for replacing". Parentheses refer to the elements (i.e. cells) of a cell array. You can use them for many things, e.g. getting a sub-array of a cell array, assigning new cells, etc., exactly like you can use parenthesis indexing with any other array class.

[iseinas]

I will search it up and read more about it. thank you so much for your time :)