While loop keep running (logical with vector )

Hi all,

My while loop running without stopping, I wanna it run until reach to logical function of a equal or smaller than 10. which should be any two numbers a=[6 3] or a=[6 6]

thanks,

clearvars;
clc;
a=[0 0];
while all(a)<=6
    z=[6 10 8 9 22 3 6];
    for i=1:2
    z(i)=z(randi(end));
    a(i)=z(i)+1
    end     
end

[Ameer Hamza]

Can you describe the condition more clearly?

[Ali Tawfik]

Hi Ameer,

Thanks for your prompt reply.

Actually I am trying to run the loop until the following condition meet:

(a) is smaller or equal to 6.

Answer 1

[Ameer Hamza]

Check this

clc;
a=[inf inf]; % start with all elemets > 6
while ~all(a <= 6)
    z=[6 10 8 9 22 3 6];
    for i=1:2
    z(i)=z(randi(end));
    a(i)=z(i)+1
    end     
end

[Ali Tawfik]

@ Ameer, It is not working !!

I got no result, a is [inf inf] which is not what I want

Thanks,

[Ameer Hamza]

There was a mistake in the while condition. Check the updated code.

[Ali Tawfik]

@ Ameer, thanks Now its working... Would you mind having a look into my new question as I have been stucked for a while !!! and need any help !

[Ameer Hamza]

I am glad to be of help! The other question seems to be a bit complicated to debug, but the main error is in the use of all() function. As you can see in my code, the comparison should be inside the all() function, not outside.

For example, instead of

all(x) > 1

you should write

all(x > 1)

Answer 2

[BOB MATHEW SYJI]

I think replacing while with if solves the problem

clearvars;

clc;

a=[0 0];

if all(a)<=6

z=[6 10 8 9 22 3 6];

for i=1:2

z(i)=z(randi(end));

a(i)=z(i)+1

end

end

[Ali Tawfik]

Thanks Bob, but I need to use while !!