How to filter set of strings with set of patterns?

I have a list of strings:

names = {'Robert', 'Bob', 'Charles', 'James', 'Jamie', 'Marie', 'Jamesbob'}

That I want to filter with a set of regular expression patterns:

patterns = {'.*ob', 'jam.*'}

How can I a list of the names which match with at least one of the patterns? (Without getting duplicates and while keeping the original order)

So would expect an output like:

{'Robert', 'Bob', 'James', 'Jamie', 'Jamesbob'}

I can find matches with a single pattern like:

regex_matches = regexpi(names, pattern{1}, 'match')

Can have multiple patterns without using a loop?

And here `regex_matches` is a cellarray of cellarrays. How would I turn this into a single level list?

(This questions sounds failry general but I couldn't find a previous question. Apologies if there is one.)

Answer 1

[Ameer Hamza]

Try this

names = {'Robert', 'Bob', 'Charles', 'James', 'Jamie', 'Marie', 'Jamesbob'};

patterns = {'.*ob', 'jam.*'};

regex_matches = cell(numel(patterns), numel(names));
for i=1:numel(patterns)
    regex_matches(i, :) = regexpi(names, patterns{i}, 'match');
end

idx = any(~cellfun(@isempty, regex_matches));
matched_names = names(idx);

Result

>> matched_names
matched_names =
  1×5 cell array
    {'Robert'}    {'Bob'}    {'James'}    {'Jamie'}    {'Jamesbob'}

[Robert Roos]

That is gorgeous, thank you!

Does this cover the unique part? If so could, could you briefly elaborate?

[Ameer Hamza]

It first matches patterns{1} with the elements in name names, and then matches patterns{2} and then take logical or of both results. This approach keeps the order of names in the matched_names same as names.