Vectorial anonymous function, given its components as anonymous functions

3 vues (au cours des 30 derniers jours)
Hello everybody,
I would like to create a vectorial anonymous function, building it up by simply "putting together" the functions corresponding to its elements (previously defined as scalar anonymous functions, of vectorial variable x). My aim is to create an anonymous function that, for instance, can be recognized by fsolve as a single anonymous function.
Here is an example:
g = @(x) x(1) + x(2).^2 ;
h = @(x) -2*x(1) + x(2).^3 ;
Now, I would like to create (formally): f(x) = [ g(x); h(x) ], without specifying it directly as:
f = @(x) [ x(1) + x(2).^2 ; -2*x(1) + x(2).^3 ] ;
but, rather, combining g and h previously defined, to end up with an anonymous function equivalent to f reported above (in such a way that, for instance, it can be fed to fsolve).
Any suggestion to do it?

Réponse acceptée

Ameer Hamza
Ameer Hamza le 22 Sep 2020
This will work
g = @(x) x(1) + x(2).^2 ;
h = @(x) -2*x(1) + x(2).^3 ;
f = @(x) [g(x); h(x)];
  2 commentaires
Marco Asperti
Marco Asperti le 22 Sep 2020
Oh as simple as that, I tried and of course it does the job. Thank you so much!
Ameer Hamza
Ameer Hamza le 22 Sep 2020
Modifié(e) : Ameer Hamza le 22 Sep 2020
I am glad to be of help!!! :)

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