Get distinct row based on row number or value

I have a table which contains products, owner and prices and products are not distinct as an example generate a dummy table using:

Upload = table();
Upload.Name = ['A'; 'B'; 'C'; 'C'];
Upload.Owner = ['D'; 'E'; 'F'; 'G'];
Upload.Price = [10; 20; 40; 30];

From the above table how can I get distinct rows based on row number. I want to get the 2nd row in case where there is a duplication the output would be:

Upload = table();
Upload.Name = ['A'; 'B'; 'C'];
Upload.Owner = ['D'; 'E'; 'G'];
Upload.Price = [10; 20; 30];

How can I achieve distinct row based on price value, where the choosen row would be the one where price is highest. The output would be:

Upload = table();
Upload.Name = ['A'; 'B'; 'C'];
Upload.Owner = ['D'; 'E'; 'F'];
Upload.Price = [10; 20; 40];

Answer 1

[Ameer Hamza]

Try this

Upload = table();
Upload.Name = ['A'; 'B'; 'C'; 'C'];
Upload.Owner = ['D'; 'E'; 'F'; 'G'];
Upload.Price = [10; 20; 40; 30];

[~, ia] = unique(Upload.Name(end:-1:1));
New_Upload1 = Upload(end-ia+1, :);

[~, idx] = splitapply(@(x) max(x), Upload.Price, findgroups(Upload.Name));
New_Upload2 = Upload(cumsum(idx), :);