How to group and convert to decimal?

The output of r is 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 1

I want to group every 8 digits and convert to decimal

Please help

[José-Luis]

Please show what you have done so far.

doc bin2dec
doc reshape

[Image Analyst]

Is the output of your r() function a string, or a numerical array (such as double or int32 or logical)? If it's a string, are there spaces between the digits?

[Sharen H]

r() function is a double value

[Image Analyst]

You mean an "array" of doubles is returned by r(), like this [0, 0, 0, 1, 0, 1, 0, etc.], not just a single double like you implied. So, it's like what Azzi assumed.

Answer 1

[Azzi Abdelmalek]

x=[ 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 1]
x=num2str(x)
x(x==' ')=[];
y=reshape(x,[],8);
out=bin2dec(y)

[Sharen H]

The answer is 0

           13

actual answer is 0

            81

whats wrong in this code

[Azzi Abdelmalek]

Ok, there is an error in reshape function

x=[ 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 1]
x=num2str(x)
x(x==' ')=[];
y=reshape(x,8,[])';
out=bin2dec(y)

[Sharen H]

Thanks a lot....

Answer 2

[Jan]

Converting from a double vector to a string and back to a double inside bin2dec is not efficient. Better convert from binary to decimal values directly:

x = [ 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 1];
d = 2 .^ (length(x)-1:-1:0) * x(:);