Converting JPG images into a cell arrays
    5 vues (au cours des 30 derniers jours)
  
       Afficher commentaires plus anciens
    
    Abdussalam Elhanashi
 le 24 Oct 2020
  
    
    
    
    
    Commenté : Walter Roberson
      
      
 le 25 Oct 2020
            Hi
I have the following code i want to convert images jpg (TrainingData) into cell arrays ,where each cell containing a 28-by-28 matrix representing a synthetic image of fingerprint 
dataDir= fullfile('Data/');
exts = {'.jpg','.png','.tif','BMP'};
imds = imageDatastore(fullfile(dataDir),...
'IncludeSubfolders',true,'FileExtensions','.jpg','LabelSource','foldernames');
countEachLabel(imds);
[TrainData, TestData] = splitEachLabel(imds, 0.5);
size(TrainData);
countEachLabel(TrainData);
for i = 1:numImages
    img = readimage(TrainData, i); 
    img  = imbinarize(img); 
end 
0 commentaires
Réponse acceptée
  Walter Roberson
      
      
 le 24 Oct 2020
        
      Modifié(e) : Walter Roberson
      
      
 le 25 Oct 2020
  
      sz = size(img);
RB = 28; CB = 28;
NRB = floor(sz(1)/RB);
LOR = sz(1) - NRB*RB;
NCB = floor(sz(2)/CB);
LOC = sz(2) - NCB*CB;
if LOR ~= 0
  rbs = [RB * ones(1,NRB), LOR];
else
    rbs = RB * ones(1,NRC);
end
if LOC ~= 0
    cbs = [CB * ones(1,NCB), LOC];
else
    cbs = CB * ones(1,NCB);
end
tiles = mat2cell(img, rbs, cbs, size(img,3));
See also mat2tiles in the File Exchange
And watch out for the titles that are not 28 x 28. This code does not assume that the image is an exact integer multiple of 28 in each direction, and it does not throw away any partial blocks.
2 commentaires
  Walter Roberson
      
      
 le 25 Oct 2020
				You are right, I had a bug in the code. I fixed it above.
Caution: your 400 x 400 image will end up with partial tiles. On each dimension, you have 14 full groups of 28, and then you have partial group of 8 to reach 400. Because of this, some of the blocks in tiles will be 8 x 28, and some will be 28 x 8, and one of them will be 8 x 8.
Plus de réponses (0)
Voir également
Catégories
				En savoir plus sur Deep Learning Toolbox dans Help Center et File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

