Effacer les filtres
Effacer les filtres

Use a for loop to evaluate

5 vues (au cours des 30 derniers jours)
Robert
Robert le 9 Fév 2013
use a for loop to evaluate the function y = {exp(x+1) if x<-1, 2+cos(pi*x) if -1<=x<5, 10*(x-5)+1 if x>=5}
e^(x+1) if x<-1
y = {2+cos(pi*x) if -1<=x<5
10(x-5)+1 if x>=5
I am having trouble correctly setting up the for loop to store the values because the final product of this, is to plot the function y(x).
  2 commentaires
Robert
Robert le 9 Fév 2013
I forgot the range for the loop which is -2 to 6 increasing by 1 each time. Sorry!
Azzi Abdelmalek
Azzi Abdelmalek le 9 Fév 2013
What have you done so far?

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Réponses (2)

Ahmed
Ahmed le 9 Fév 2013
according to my little knowledge if you need to store this value for every loop in a Matrix where every inner for loop represent a row you can do this
if
y=zeros(9)
x=input('x=')
for i1=-2:6
y(i1)=.....
end
then y will be an array whose values are stored in the above Zero Matrix
Does this help ?
  1 commentaire
Image Analyst
Image Analyst le 9 Fév 2013
Modifié(e) : Image Analyst le 9 Fév 2013
You cannot have zero or negative indexes, like -2 or -1 or 0. You can either add 3 to i1, or use a counter like I did in my Answer.

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Image Analyst
Image Analyst le 9 Fév 2013
Modifié(e) : Image Analyst le 9 Fév 2013
Try something like this:
index = 1;
for x = -2 : 1 : 6
if x < -1
% Insert code/formula here
y(index) = .........whatever.....
else if x >= -1 && x < 5
% Insert other code/formula here
else
% x >= 5
% Insert code/formula here
end
index = index + 1;
end
% Plot it.
plot(x,y, 'bo-', 'LineWidth', 3, 'MarkerSize', 15);
title('Plot of y vs. x', 'FontSize', 25);
  2 commentaires
Robert
Robert le 10 Fév 2013
Thank you. I will ask if you could generically go where the y(index) first appears. Basically what would the "whatever" be? I'm still very new to Matlab
Image Analyst
Image Analyst le 10 Fév 2013
You insert the appropriate formula from your question:
y = e^(x+1) if x<-1
y = {2+cos(pi*x) if -1<=x<5
y = 10(x-5)+1 if x>=5

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