How to reshape array based on another array with nan values

I want to see if there is a specific function that will help me do this:

I have a 10x1 array.

a = [2 6 5 4 7 2 3 2 3 1];

I would like to reshape it to fit the same shape as logical array b (with nan values as 0).

b = [1 1 1 0;1 1 1 1;1 0 1 1]

Is there an easy way to reshape my array in that mold?

Answer 1

[Bruno Luong]

a = [2 6 5 4 7 2 3 2 3 1]
b = [1 1 1 0;1 1 1 1;1 0 1 1]

A = nan(size(b'));
A(b'==1) = a;
A = A.'

[Michael Burnett]

Thank you!!

Answer 2

[Abolfazl Chaman Motlagh]

b=logical(b);
A=zeros(size(b));
A(b)=a;
A(~b)=nan(sum(~b,'all'),1);

output:

A =

     2     4     2   NaN
     6     7     3     3
     5   NaN     2     1

[Abolfazl Chaman Motlagh]

or just

b=logical(b);
A=nan(size(b));
A(b)=a;

[Michael Burnett]

Lol, I'm quite new to MATLAB, so this is very helpful. Thanks