Discrete Fourier Transform MATLAB Code

7 vues (au cours des 30 derniers jours)
Sanaz Da
Sanaz Da le 8 Nov 2020
This code computes the DFT from time domain.
Can anybody see the code below and help me to get the right answer?
my problem is:
when I change N value, for example, to 4, 5, 10 ,or other values.
X(1) changes with that. but I think X(1) must be the same for every value of N.
just like the shape below: the N value changes but the vertical value is the same.
I appreciat if you help me.
Thank you.
clear; clc;
% %% Analytical
N=4;
k=0:N-1;
X=zeros(N,1);
t=k/N;
%x=5+2*cos(2*pi*t-pi/2)+3*cos(4*pi*t)
x=abs((1-(0.012.*(pi.*52.*(t-0.3721)).^2)).*exp(-(pi.*52.*(t-0.3721).^2)))
sum(x)/N
for k=0:N-1
for n=0:N-1
X(k+1)=X(k+1)+x(n+1)*-i^(n*k)/N;
end
end
k1=[0:N-1];
stem(k1,abs(X))
% xlim([0 1])
% ylim([-1 1])

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