Format long error in function
15 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
ahmed saheed
le 9 Nov 2020
Commenté : ahmed saheed
le 9 Nov 2020
Hi guys,
I am attempting secant method in matlab, my function works perfectly well and outputs results to 4 decimal places. however i want to increase the number of decimal places and i am trying to use format long, however it does not work. Can you kindly take a look at my code
function approx = secant(f,x0,x1,nmax,tol)
format long
i = 2;
p0 = f(x0);
p1 = f(x1);
while i < nmax
x2 = x1 - (x1-x0)*p1/(p1-p0);
if abs(x2-x1)<tol
break
end
i = i + 1;
x0 = x1;
x1 = x2;
p0 = p1;
p1 = f(x2);
disp(x2)
end
approx = x2;
end
Thank you!
0 commentaires
Réponse acceptée
Geoff Hayes
le 9 Nov 2020
ahmed - consider using fprintf and specifiying the number of integers to the right of the decimal point that you are interested. For example, change
disp(x2)
to
fprintf('%.8f\n', x2);
where the .8 indicated that you want to show 8 integers to the right of the decimal point.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur LaTeX dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!