Format long error in function

15 vues (au cours des 30 derniers jours)
ahmed saheed
ahmed saheed le 9 Nov 2020
Commenté : ahmed saheed le 9 Nov 2020
Hi guys,
I am attempting secant method in matlab, my function works perfectly well and outputs results to 4 decimal places. however i want to increase the number of decimal places and i am trying to use format long, however it does not work. Can you kindly take a look at my code
function approx = secant(f,x0,x1,nmax,tol)
format long
i = 2;
p0 = f(x0);
p1 = f(x1);
while i < nmax
x2 = x1 - (x1-x0)*p1/(p1-p0);
if abs(x2-x1)<tol
break
end
i = i + 1;
x0 = x1;
x1 = x2;
p0 = p1;
p1 = f(x2);
disp(x2)
end
approx = x2;
end
Thank you!

Réponse acceptée

Geoff Hayes
Geoff Hayes le 9 Nov 2020
ahmed - consider using fprintf and specifiying the number of integers to the right of the decimal point that you are interested. For example, change
disp(x2)
to
fprintf('%.8f\n', x2);
where the .8 indicated that you want to show 8 integers to the right of the decimal point.
  1 commentaire
ahmed saheed
ahmed saheed le 9 Nov 2020
Hi Geoff
Thank you for the clarity.
It worked :)

Connectez-vous pour commenter.

Plus de réponses (0)

Produits


Version

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by