Indexing through an array

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Austin Shipley
Austin Shipley le 17 Nov 2020
Commenté : Austin Shipley le 17 Nov 2020
This program is designed to approximate cubed roots based on user input values of the number they want to approximate and their estimate. The loop iterates until the error is less than 1e-9.
I am trying to store all of my estimate values into a vector array and plot them on a graph, but I keep getting an error saying that my index values exceed the array elements. Any clarification about how to resolve this issue would be greatly appreciated.
num = input('Enter a number you would like to find the cubed root of: ')
est = input('Enter your initial estimate: ')
err = abs(num - est.^3)
est(1) = est
k = 2;
while err > 1e-9
est(k+1) = (1/3)*(2.*est(k)+num./est(k.^2));
err = abs(num - est(k.^3));
k = k + 1;
end
plot(1:length(est),est)
fprintf('The cubed root of %g is approximately %.3f',num,est)

Réponse acceptée

David Hill
David Hill le 17 Nov 2020
num = input('Enter a number you would like to find the cubed root of: ');
est = input('Enter your initial estimate: ');
err = abs(num - est^3);
k = 2;
while err > 1e-9
est(k) = (1/3)*(2*est(k-1)+num./(est(k-1)^2));
err = abs(num - est(k)^3);
k = k + 1;
end
plot(1:length(est),est);
fprintf('The cubed root of %g is approximately %.3f',num,est(end));
  1 commentaire
Austin Shipley
Austin Shipley le 17 Nov 2020
That worked perfectly! Thank you so much! I never really thought to tweak the array indices since that was a provided formula in my homework.

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