can anyone explain me this code??
Afficher commentaires plus anciens
x5;
x8=load('hearttest.txt');
c4=size(x8)*[1;0];%calculating size of matrix.
u1=size(x8)*[0;1];
x6=x8;
%==========================================================
per=80;
per1=20;
al=0.1;
pe=per/100;
v=round(pe*c3);
%==========================================================
%
%==================================================================
%separating the input attributes and the target from the input file
%==================================================================
%Reading input in an array
for s1=1:m
for i=1:c3
if(x5(i,u)==(s1-1))
for(j=1:u)
temp=x5(s1,j);
x5(s1,j)=x5(i,j);
x5(i,j)=temp;
end
end
end
end
%==================================================================
%==================================================================
%TARGET CLASS vectors
%
for i=1:c3
for j=1:u
if((j==u))
t(i)=x5(i,j);
end
end
end
%==================================================================
for i=1:c3
for j=1:u-1
x(i,j)=x5(i,j);
end
end
%==================================================================
%INPUT vectors
for i=1:c3
for j=1:u-1
if x(i,j)==0
x(i,j)=.05;
end
end
end
%==================================================================
%==================================================================
%Normalizing the datas.
q2=size(x)*[0;1];
p2=size(x)*[1;0];
y=max(x,[],1);
z=min(x,[],1);
for i=1:q2
if y(i)~=z(i)
e(i)=y(i)-z(i);
else
e(i)=1;
z(i)=0;
end
end
for i=1:p2
for j=1:q2
x(i,j)=(x5(i,j)- z(j))/(e(j));
end
end
x8;
q5=size(x8)*[0;1];
p5=size(x8)*[1;0];
y=max(x8,[],1);
z=min(x8,[],1);
for i=1:q5
if y(i)~=z(i)
e(i)=y(i)-z(i);
else
e(i)=1;
z(i)=0;
end
end
for i=1:p5
for j=1:q5
x8(i,j)=(x8(i,j)- z(j))/(e(j));
end
end
x8;
%==================================================================
%==================================================================
%STEP1:
%Initialising then weight matrix.
%==================================================================
for i=1:u-1
for j=1:4
w(i,j)=x(j,i);
end
end
2 commentaires
Azzi Abdelmalek
le 27 Fév 2013
Can your question be more precise? because I don't see how is it possible to explain all these lines of code.
chinmay
le 27 Fév 2013
Réponse acceptée
Plus de réponses (0)
Catégories
En savoir plus sur Deep Learning Toolbox dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!