Effacer les filtres
Effacer les filtres

Weights for Numerical Integration on the Sphere

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Adam
Adam le 5 Mar 2013
Hi, I'm just dealing with numerical integration (quadrature) on the sphere. I know positions of nodes but don't know how to compute integration weights that should ensure correct integration of all spherical harmonics functions up to given order.
Thank you fo your answers. Adam
  2 commentaires
Youssef  Khmou
Youssef Khmou le 5 Mar 2013
hi, correct integration means the result can not exceed 4/3piR^3 ? and weights based on nodes's distances from (0,0,0) ?
Adam
Adam le 5 Mar 2013
hi, the correct integration means that it provides exact numerical integration of product of spherical harmonics up to a given sum of orders. When the integration in Eq.(1) is approximated by the sum in eq.(2) <https://www.dropbox.com/s/4iiv991xzm9ktln/pic.png?m> where \Omega is (theta,phi) and j=1,... is the number of points sampling the sphere surface. Thanks

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