How to copy a sub-matrix/vector along diagonal of a larger matrix with varying number of sub-matrices?
Afficher commentaires plus anciens
I want to create a matrix below where I copy A = [1 2 3] allow the diagonal of a matrix.
[ 1 2 3 0 0 0 0 0 0 0 0 0
0 0 1 2 3 0 0 0 0 0 0
0 0 0 0 0 0 1 2 3 0 0 0
0 0 0 0 0 0 0 0 0 1 2 3]
I know I can use blkdiag(A ,A, A, A) which will do the job however the number of parameters vary in my code. Sometimes, there may be five A vectors or 20 A vectors that I need to create such a matrix. Let's say this is a variable that the user inputs
How can I do this efficiently in code?
2 commentaires
Sean de Wolski
le 8 Mar 2013
I'm not clear, how would result be different with five vectors or twenty?
John
le 8 Mar 2013
Réponse acceptée
Plus de réponses (3)
Azzi Abdelmalek
le 8 Mar 2013
Modifié(e) : Azzi Abdelmalek
le 8 Mar 2013
a=[1 2 3]
n=5
d=[a zeros(1,numel(a)*(n-1))]
out=cell2mat(arrayfun(@(x) circshift(d,[0 (n-1)*x]),(0:n-1)','un',0))
EDIT
a=[1 2 3]
n=5
d=[a zeros(1,numel(a)*(n-1))]
out=cell2mat(arrayfun(@(x) circshift(d,[0 numel(a)*x]),(0:n-1)','un',0))
1 commentaire
Azzi Abdelmalek
le 8 Mar 2013
Modifié(e) : Azzi Abdelmalek
le 8 Mar 2013
There was an error, check this
n=5 % number of matrices
a=[1 2 3]
d=[a zeros(1,numel(a)*(n-1))]
out=cell2mat(arrayfun(@(x) circshift(d,[0 numel(a)*x]),(0:n-1)','un',0))
Azzi Abdelmalek
le 8 Mar 2013
Modifié(e) : Azzi Abdelmalek
le 8 Mar 2013
n=10
a=[1 2 3]
s= ['@(x1)blkdiag(x1' sprintf(',x%d',ones(1,n-1)) ')']
blkdiagn=str2func(s)
out=blkdiagn(a)
George Papazafeiropoulos
le 8 Mar 2013
0 votes
e = ones(n,1);
A = full(spdiags([e 2*e 3*e], 0:2, n, n+2))
A = full(spdiags(A, 0:5, n, n+5))
A = full(spdiags(A, 0:8, n, n+8))
George Papazafeiropoulos
Catégories
En savoir plus sur Operating on Diagonal Matrices dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!