Effacer les filtres
Effacer les filtres

How to sort numbers in a char

4 vues (au cours des 30 derniers jours)
arthur doroshev
arthur doroshev le 30 Nov 2020
Commenté : arthur doroshev le 30 Nov 2020
Hello,
I have a difficulty to make a sorting in a char. I need to sort the next char by the second number of each big Letter, for example:
G([1.1277],u1+[2.9793],[0.3143])+G([0.2594],u1+[3.8532],[0.31232])+Y([4.1689],u1+[9.0615],[0.024204])+D([1.2424],u1+[1.5934],[0.024204])
it should be like that as a result:
Y([4.1689],u1+[9.0615],[0.024204])+G([0.2594],u1+[3.8532],[0.31232])+G([1.1277],u1+[2.9793],[0.3143])+D([1.2424],u1+[1.5934],[0.024204])
If someone could help me with that, it will be very helpful
Thank a lot :)
  1 commentaire
Rik
Rik le 30 Nov 2020
You need to solve difficult problems step by step.
  1. Split the char into the terms
  2. Extract the relevant number from each term
  3. Use the second output of sort to determine the order
  4. Apply the sort to the tems
  5. Stich the terms back together

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Réponse acceptée

Stephen23
Stephen23 le 30 Nov 2020
str = 'Y([4.1689],u1+[9.0615],[0.024204])+G([0.2594],u1+[3.8532],[0.31232])+G([1.1277],u1+[2.9793],[0.3143])+D([1.2424],u1+[1.5934],[0.024204])';
spl = regexp(str,'[A-Z]\([^\)]+\)','match');
vec = sscanf(str,'%*[A-Z]([%*f],u1+[%f],[%*f])+');
[~,idx] = sort(vec,'descend');
out = join(spl(idx),'+');
out = out{1}
out = 'Y([4.1689],u1+[9.0615],[0.024204])+G([0.2594],u1+[3.8532],[0.31232])+G([1.1277],u1+[2.9793],[0.3143])+D([1.2424],u1+[1.5934],[0.024204])'
  1 commentaire
arthur doroshev
arthur doroshev le 30 Nov 2020
Thank you very much Stephen Cobeldick

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