Comparing 2 vectors: finding closest point
8 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
If I have 2 vectors, say:
x=[1 2 3 4 5];
y=[0 1.1 1.5 1.6 2.4 4.1 4.7 5 5.7];
I want to find the index of the closest match in y, for each index in x. So, for x(1) it would be y(2), for x(2) it would be y(5), etc. Also, it would be nice to have the counts of y values for each x index that occur before the next x index. For example, x(1) it would be 3 (1.1, 1.5, 1.6). x(3) it would be 0.
I was trying to use histc for this, with x specifying the edges, but didn't know if there was a different approach.
0 commentaires
Réponses (1)
Azzi Abdelmalek
le 12 Mar 2013
Modifié(e) : Azzi Abdelmalek
le 12 Mar 2013
x=[1 2 3 4 5];
y=[0 1.1 1.5 1.6 2.4 4.1 4.7 5 5.7];
for k=1:numel(x)
[val,idx]=min(abs(y-x(k)));
xx(k)=y(idx);
end
0 commentaires
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!