How to solve this matrix using inverse function?

13 vues (au cours des 30 derniers jours)
Joseph
Joseph le 15 Mar 2013
I want to use the inverse function (inv) on this 10 x 10 matrix but I keep getting all this Inf in place of the numbers.
The matrix goes as follows,
clc,clear all
a = [1 2 3 4 5 6 7 8 9 10];
b = [21 22 23 24 25 26 27 28 29 30];
c = [11 12 13 14 15 16 17 18 19 20];
d = [31 32 33 34 35 36 37 38 39 40];
f = [41 42 43 44 45 46 47 48 49 50];
g = [61 62 63 64 65 66 67 68 69 70];
h = [51 52 53 54 55 56 57 58 59 60];
i = [81 82 83 84 85 86 87 88 89 90];
j = [91 92 93 94 95 96 97 98 99 100];
e = [1 2 3 4 5 6 7 8 9 10];
aa = sum(a);
bb = sum(b);
cc = sum(c);
dd = sum(d);
ff = sum(f);
gg = sum(g);
hh = sum(h);
ii = sum(i);
jj = sum(j);
ee = sum(e);
AA = [a ;b ;c ;d ;e ;f ;g ;h ;i ;j];
b = [aa ;bb ;cc ;dd ;ff ;gg ;hh ;ii ;jj ;ee];
Res = inv(A)
The result I am getting is this one,
Warning: Matrix is singular to working precision.
> In borrame at 39
Res =
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Inf Inf Inf Inf Inf Inf Inf Inf Inf Inf
Why if the command (inv) not working? Please help.

Réponse acceptée

James Tursa
James Tursa le 15 Mar 2013
Assuming inv(A) is a typo and you really meant inv(AA):
"a" and "e" are the same, so you have two rows in AA that are the same. This linear dependency creates a singular matrix AA.

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