Inserting a function in a matrix.
21 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Jason Psimopoulos
le 7 Déc 2020
Modifié(e) : Jason Psimopoulos
le 9 Déc 2020
I am trying to solve the system above.I think I got right the first part of the quation with a for loop(code bellow) L = 51;
ws1 = 0.4*pi;
wp1 = 0.5*pi;
Ks1 = 1;
Kp = 2;
wo = (ws1+wp1)/2;
G = 1000;
w = [0:(G)]*pi/G;
W = Ks1*(w<=ws1) + Kp*(w>=wp1)
D = (wo>=w);
N=(L-1)/2
m=0:N
k=1:1001
for i = 0:N
F(i+1,:)=sum(arrayfun(@(k) (W(k).^2).*D(k).*cos(w(k).*i), 1:1000))
end
I am struggling though in the second part.My code looks like this but it does not seem to work.
for i = 0:N
for p = 0:N
F2=@(k)(W(k).^2).*D(k).*(cos(w(k).*i).*(cos(w(k).*p))')
end M[i+1,p+1]=sum[arrayfun(@(k) F2(k), 1:1000)]
end
Does anyone know how I could possibly fix that.I also download the symbolic math toolbox but I was not able to find something to help me with that.
2 commentaires
Théophane Dimier
le 8 Déc 2020
Modifié(e) : Théophane Dimier
le 8 Déc 2020
Hi,
that line looks a bit weird:
end M[i+1,p+1]=sum[arrayfun(@(k) F2(k), 1:1000)]
What do you want to do there? you should not have a statement after the end. Also, functions are called with parenthese () and not brackets []. To index arrays one should also use parentheses () and not brackets [] (unlike python or C)
Considering that it was a typo, would the following work?
M(i+1,p+1)=sum(arrayfun(@(k) F2(k), 1:1000))
end
Réponse acceptée
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!