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matrix manupulation and reading diagonally

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NIKHIL
NIKHIL le 8 Déc 2020
Commenté : NIKHIL le 11 Déc 2020
Hello Team,
i have a matrix
Matrix_test = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16];
I want to read the matrix in the order mentioned in the matrix.
Starting from left bottom (1), then right top (2) and then again 2nd diagonal from left (3,4) and then 2nd right diagonal (5,6) and so on and so forth.
Please support in resolving it.
Edit : i there any way to create this kind of matrix for any n-by-n matrix automatically. i have created this Matrix_test manually but if i want 8x8 matrix in similar pattern . How to create it through generic code.
Thanks in advance.

Réponse acceptée

Stephan
Stephan le 8 Déc 2020
This function may help:
M = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16]
MyResult = readDiag(M)
function R = readDiag(M)
R = cell(2,numel(diag(M)));
for k = 1:numel(diag(M))-1
R{1,k} = diag(M,-numel(diag(M))+k);
R{2,k} = diag(M,numel(diag(M))-k);
end
R = reshape(R,[],1);
R = [R; {diag(M)}];
R = cell2mat(R);
end
result is:
M =
13 10 5 2
7 14 11 6
3 8 15 12
1 4 9 16
MyResult =
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
  2 commentaires
NIKHIL
NIKHIL le 11 Déc 2020
Thank your for your solution.
NIKHIL
NIKHIL le 11 Déc 2020
Hello Stephen, I have edited one additional question related to this query. How to create similar type of Matrix_test automatically with some code. can you please revert back to this query also ?

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Plus de réponses (1)

Bruno Luong
Bruno Luong le 8 Déc 2020
Modifié(e) : Bruno Luong le 8 Déc 2020
Matrix_test = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16]
[m,n]=size(Matrix_test);
[i,j]=ndgrid(1:m,1:n);
jmi = j(:)-i(:);
[~,is]=sortrows([-abs(jmi) jmi]);
Matrix_test(is)
  4 commentaires
Bruno Luong
Bruno Luong le 11 Déc 2020
Create matrix with dimension m x n.
m=8; n=8;
[i,j]=ndgrid(1:m,1:n);
jmi = j(:)-i(:);
[~,is]=sortrows([-abs(jmi) jmi]);
M=zeros(m,n);
M(is)=1:m*n
NIKHIL
NIKHIL le 11 Déc 2020
Thank you so much Bruno for quick response.
It is working really good

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