Hex 01A9 to 16-binary?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
WARRIOR24
le 16 Déc 2020
Modifié(e) : Stephen23
le 17 Déc 2020
I am trying to convert this input 01A9 into binary
4bit Hex input
01A9
16bit Binary Output
0000 0001 1010 1001
**no spaces
0 commentaires
Réponse acceptée
Walter Roberson
le 16 Déc 2020
H = '01A9';
dec2bin(sscanf(H, '%4x'),16)
Note that the result will be character.
H can have more than 4 characters, and will be interpreted 4 characters at a time from the beginning . So if H is not an exact multiple of 4 characters, this particular algorithm will not implicitly pad from the begining with 0's -- only the last group will be 0 padded.
dec2bin(sscanf('01A9876', '%4x'),16)
This was interpretered as 01A9 (0)876.
If you needed to be padded with leading 0s implicitly then that could certainly be programmed.
0 commentaires
Plus de réponses (2)
James Tursa
le 16 Déc 2020
Modifié(e) : James Tursa
le 16 Déc 2020
E.g., if H is not too big:
H = '01A9';
B = dec2bin(hex2dec(H),numel(H)*4)
Otherwise you will need some form of a loop (explicit or hidden in a function call). E.g.,
C = arrayfun(@(h)dec2bin(hex2dec(h),4),H,'uni',false);
B = [C{:}]
0 commentaires
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!