How can i convert this linear equation into a form which i can use linsolve() function?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/471332/image.png)
I wrote a code like;
function [a,b]=lin_reg(x,y)
a=0;
b=0;
for i = 1:length(x)
for j = 1:length(y)
a=(y(j)-b)/x(i);
b=y(j)-a*x(i);
end
end
end
But these code didn't help me to pass my tests, so i need an equation which i can use linsolve() function.
Thanks in advance.
0 commentaires
Réponses (1)
Pratyush Roy
le 29 Déc 2020
Hi,
Assuming that both x and y are arrays of shape 1*n, the following code snippet might be helpful
x_new = [x' ones(n,1)];
coeff = linsolve(x_new,y');
Here coeff is a 1*2 array where
a = coeff(1);
b = coeff(2);
Hope this helps!
0 commentaires
Voir également
Catégories
En savoir plus sur Operating on Diagonal Matrices dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!