Effacer les filtres
Effacer les filtres

Subscript indices must either be real positive integers or logicals.

2 vues (au cours des 30 derniers jours)
Ahmed Saleem
Ahmed Saleem le 31 Déc 2020
Commenté : Rik le 31 Déc 2020
Error in line 21
Plz help me with this. Whenever I sign them arrays it gives me error but without array it doesnt. Im using arrays to plot it.
clc
% Part a
% ps1=exp (16.59158-(3643.31/(t-33.424)))
% ps2=exp (14.25326-(2665.54/(t-53.424)))
% T = 318.15 K and x1 = 0.25
t=318.15;
p=zeros(1,21);
y1=zeros(1,21);
y2=zeros(1,21);
for i=1:0.05:2
syms x2 ps1 ps2 p y1 y2
x1=i-1;
x2=1-x1;
k=((i-1+0.05)/0.05);
ps1 = exp (16.59158-(3643.31/(t-33.424)));
ps2 = exp (14.25326-(2665.54/(t-53.424)));
% eqn1= p== (x1*ps1)+(x2*ps2);
p(1,k)= double(solve(p== (x1*ps1)+(x2*ps2)));
% eqn2= y1== (x1*ps1)/p;
y1(1,k)= double(solve(y1== (x1*ps1)/p(1,k)))
% eqn3= y2== (x2*ps2)/p;
y2(1,k)= double(solve(y2== (x2*ps2)/p(1,k)))
end

Réponse acceptée

Rik
Rik le 31 Déc 2020
Welcome to the wonderful world of floating point numbers. Just like 1/3 cannot be represented exactly with decimal values (meaning 3*(1/3) will be 0.9999), Matlab can't always store the numbers with an exact representation. This causes the rounding errors you see:
for i=1:0.05:2
k=((i-1+0.05)/0.05);
fprintf('k=%.20f\n',k)
end
k=1.00000000000000000000 k=2.00000000000000088818 k=3.00000000000000133227 k=3.99999999999999777955 k=4.99999999999999822364 k=5.99999999999999911182 k=7.00000000000000000000 k=8.00000000000000177636 k=8.99999999999999822364 k=9.99999999999999822364 k=11.00000000000000000000 k=12.00000000000000177636 k=13.00000000000000177636 k=13.99999999999999822364 k=15.00000000000000355271 k=16.00000000000000000000 k=17.00000000000000000000 k=18.00000000000000000000 k=18.99999999999999644729 k=20.00000000000000355271 k=21.00000000000000000000
You can use round to force an integer value.
  2 commentaires
Ahmed Saleem
Ahmed Saleem le 31 Déc 2020
can you show me the syntac to use round?

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