MATLAB Practice questions solution
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Hello all,
I am new to MATLAB and I am still trying to learn it by myself. I was trying to solve the questions posted by MATLAB. I know I didn't use the double function as suggested so please enlighten me with your ideas and let me know if i was at least close to what the problem is asking for:
Problem(link: https://www.mathworks.com/services/training/certification/ml-professional-exam/practice-test.html)
The provided text file (readings.txt) contains a timestamp broken up into year, month, day, hour, minute, second, and timezone components, as well as a reading from a sensor. Write a script that reads the data from the file using the textscan function.
The script must:
- Convert the timestamps into single numeric serial date numbers stored in a variable named dates
- Ignore the timezone component of the timestamp by not reading it into the workspace
- Place numeric values for the readings in a single array of type double with a variable name of readings
clc
clear all
fileID1 = fopen('readings.txt');
dates = textscan(fileID1, '%s %s %s %s %s %s %s %s');
fclose(fileID1);
whos dates;
celldisp(dates)
fileID2=fopen('readings.txt')
C=textscan(fileID2, '%q %q %q %q %q %q %*q %q');
fclose(fileID2);
whos C;
celldisp(C)
fileID3=fopen('readings.txt');
D=textscan(fileID3,'%*q %*q %*q %*q %*q %*q %*q %q');
fclose(fileID3);
whos D;
celldisp(D)
1 commentaire
DEEPAK RAJ B
le 20 Jan 2024
add one section to the end of the script
Réponses (3)
Image Analyst
le 3 Jan 2021
0 votes
Perhaps datenum()?
>> d=datenum(now)
d =
738159.473416505
7 commentaires
Ali Awada
le 4 Jan 2021
Image Analyst
le 4 Jan 2021
It turns complicated date formats into a floating point number, which is easier to sort. So it does this:
- Convert the timestamps into single numeric serial date numbers stored in a variable named dates
If you want more specific help, then attach the 'readings.txt' file which you forgot to attach. Because otherwise we really don't know what format your "timestamps" are in. There is a dizzying variety of time and date formats and functions. It can get really confusing.
Ali Awada
le 5 Jan 2021
Image Analyst
le 5 Jan 2021
You should have tried datenum like I suggested. I did and it seems to work fine:
t = readtable('readings.txt')
d = datenum(t.Year, t.Month, t.Day, t.Hour, t.Minute, t.Second)
readings = t.Reading
plot(d, readings, 'b.-', 'LineWidth', 2, 'MarkerSize', 30);
grid on;
title('Alis Homework', 'FontSize', 20);
xlabel('Date/Time Stamp', 'FontSize', 20);
ylabel('Reading', 'FontSize', 20);

Ali Awada
le 10 Jan 2021
Image Analyst
le 10 Jan 2021
Then just use the first 3 lines and skip the rest of the lines that have to do with plotting.
Ali Awada
le 11 Jan 2021
Kazem Gheysari
le 24 Août 2021
Modifié(e) : Kazem Gheysari
le 24 Août 2021
clear
fileID = fopen('readings.txt');
C_text = textscan(fileID,'%s',8,'Delimiter',' ');
C = textscan(fileID,'%f %f %f %f %f %f EST %f','Delimiter',' ','EmptyValue',-Inf);
fclose(fileID);
Y = C{1,1};
M = C{1,2};
D = C{1,3};
H = C{1,4};
MN= C{1,5};
S = C{1,6};
dates = datenum(Y,M,D,H,MN,S)
readings = C{1,7};
1 commentaire
Image Analyst
le 24 Août 2021
What is matlab1.com? (I did not click your link because there is no explanation)
syms y(t);
dsolve(diff(y)==y, y(0)==1, 'Expansion Point', 0)
1 commentaire
syms y(t);
dsolve(diff(y)==y, y(0)==1, 'ExpansionPoint', 0)
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