Search string array column for a specific string
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I have a 1000 x 30 string array. I'm trying to search column 5 for a specific set of strings and output the rows in which they're found.
Example Code:
I've put a sample below. I'm trying to only search column 5 of X for the terms in search and spit out which row they're in. I'm not sure how to go about this. I've tried
while i < size(search(1,:),2)
[row,col] = find(strcmp(X,search((i)));
i = i + 1;
end
but this searches the entire row and not just column 5 for the terms. I also need the rows which include other terms in addition to the search terms like the 1st row.
>> search =
1×4 cell array
{'apple'} {'banana'} {'orange'} {'grapefruit'}
>> X(1:8,1:6)
ans =
8×6 string array
"0" "0" "0" "0" "apple peanut" "0"
"0" "0" "apple" "0" "apple" "0"
"0" "0" "0" "apple" "apple" "0"
"0" "0" "apple" "0" "banana" "0"
"0" "0" "0" "0" "banana" "0"
"0" "0" "banana" "0" "orange pickle" "0"
"0" "0" "pickle" "0" "orange" "0"
"0" "0" "0" "0" "grapefruit" "0"
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Ive J
le 11 Jan 2021
Have you tried ismember? You only need column 5, but you fed first argument of strcmp with the whole string array.
rowIdx = find(ismember(X(:, 5), search)); % row indices of X which contain any of search elements
3 commentaires
Ive J
le 11 Jan 2021
If your entire string array follows your example, so you can use contains:
rowIdx = find(contains(X(:, 5), search));
But if the text pattern is more complex, you can use regexp with some efforts.
Plus de réponses (1)
Walter Roberson
le 11 Jan 2021
search = {'apple', 'banana', 'orange', 'grapefruit'}
searchcol = 3
X = [
"0" "0" "0" "0" "apple" "0"
"0" "0" "apple" "0" "apple" "0"
"0" "0" "0" "apple" "apple" "0"
"0" "0" "apple" "0" "banana" "0"
"0" "0" "0" "0" "banana" "0"
"0" "0" "banana" "0" "orange" "0"
"0" "0" "pickle" "0" "orange" "0"
"0" "0" "0" "0" "grapefruit" "0"
]
[wasfound, fruitidx] = ismember(X(:,searchcol), search)
matching_rows = find(wasfound)
matching_fruit_number = fruitidx(wasfound)
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