call consecutive variables for loop

2 vues (au cours des 30 derniers jours)
Ana
Ana le 17 Avr 2013
Hi,
I have variables in the workspace with the following names: A2010,A2011, A2012.....
Need to to the following for each variable:
AA2010=A2010';
t = AA2010>=2000;
z = [find([true,diff(t)~=0]) numel(AA2010)+1];
idx = [z(1:end-1);z(2:end)-1];
i1 = idx(:,t(idx(1,:)));
i2 = i1(:,(diff(i1) + 1) >= 1);
out = arrayfun(@(x)AA2010(i2(1,x):i2(2,x)),1:size(i2,2),'un',0);
L=length(out);
I'm trying to use:
for i=2010:2037
eval(['A' num2string(i) '=i'])
end
however no results came out...
Any suggestions?
Thanks

Réponses (3)

Azzi Abdelmalek
Azzi Abdelmalek le 17 Avr 2013
It's not num2string but num2str. Also it's not a good idea to use eval

Walter Roberson
Walter Roberson le 17 Avr 2013

Jan
Jan le 17 Avr 2013
To mention it the third time: Do not do this. Storing indices inside the names of variables is a really bad idea, as you see already. Using an array instead, or two arrays, where one contains the values and the other the idnices, would be much clearer and easier to handle.

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