Selection of row from a matrix

1 vue (au cours des 30 derniers jours)
raj singh
raj singh le 20 Avr 2013
i have a matrix,and i want remove that row in which numbers repeated
A= [3 5 5
6 9 1
7 5 7
2 4 6];
Ans: A=[6 9 1;2 4 6]
i used "for loop" for this problem, i want to ask there is any direct command to find the Ans. pls give me the suggestion.....

Réponse acceptée

per isakson
per isakson le 20 Avr 2013
Post the question at Cody:). It's a little exercise with logicl indexing.
>> A( any( diff( sort( A, 2 ), 1, 2 ) == 0, 2 ), : ) = []
A =
6 9 1
2 4 6
>>
  4 commentaires
per isakson
per isakson le 20 Avr 2013
Works here
A= [1 1 1 2
1 2 3 4
1 2 4 5
3 4 3 3];
A( any( diff( sort( A, 2 ), 1, 2 ) == 0, 2 ), : ) = []
A =
1 2 3 4
1 2 4 5
>>
raj singh
raj singh le 20 Avr 2013
:) yaa, its working, it was my fault. thanks

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