how to extract the bounding box area as segmented object from video frame?...I have been trying imcrop but the rectangle cropped out is not as same as bbox rectangle.
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I am using computer vision toolbox.. this is the code..Is there any other way of doing it??
please help..thankyou in advance!
crop=bbox(:,); % all bbox that hav objects
crop=transpose(crop); % bbox as crop in row major as for rectangles
num = size(crop,1);
for k = 1: num
crop(k,2)=crop(k,2)-crop(k,3); % ymin is required but ymax is in upper left corner
temp=crop(k,3); % swapping height and width as required in rectangle! crop(k,3)=crop(k,4); crop(k,4)=temp;
[Xtest,Ytest,itest,Rtest]=imcrop(image,crop(k,:));
imshow(itest);
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Image Analyst
le 24 Avr 2013
I don't know what bbox is. Don't use image as the name of your image variable because it's the name of a built-in function. Simply crop like this:
croppedImage = imcrop(fullImage, [leftColumn, topRow, numberOfColumns, numberOfRows]);
You have to figure out how to get leftColumn, topRow, numberOfColumns, numberOfRows.
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Image Analyst
le 29 Avr 2013
I don't know what step() does, but in all the MATLAB functions that I can think of when it wants a rectangle, it's [xStart, yStart, xSize, ySize]. Check with the documentation for step() - for example make sure it's not using row, column instead of x,y.
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Anand
le 29 Avr 2013
It seems to work for me...The rectangle specification provided by the vision.BlobAnalysis object is the same as that required by imcrop.
im = padarray(strel('disk',100,0).getnhood,[50 25],'pre');
hblob = vision.BlobAnalysis;
[area,centroid,bbox] = step(hblob,im);
>> bbox
bbox =
26 51 201 201
out = imcrop(im,bbox);
imshow(out);
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