Applying an integer to a specific cell of a matrix
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I need to apply a single integer across a group of cells in a matrix. I honestly have no idea how to do this. Here's the code that im working with right now
x = [0:0.1:3];
y = [-2:0.13:2];
Load = 0;
for (x = 1:31)
for (y = 1:31)
Load(x,0) = 10;
end
end
But that and several other variations i've tried are not working whatsover.
The Integer "Load" needs to be inserted into all values of x where y = 0.
How can I do this?
4 commentaires
DEEPAK Chekuri
le 3 Fév 2021
In this case 'y' will never be zero.
however if you have ,another list of y(which has zeros) ,then try this
for i=1:31
if y[i]==0
x[i]=Load;
end
end
Stephen23
le 3 Fév 2021
@DEEPAK Chekuri: that is not valid MATLAB code. You seem to be mixing up languages.
Réponses (1)
Pratyush Roy
le 10 Fév 2021
Modifié(e) : Pratyush Roy
le 10 Fév 2021
Hi Noah,
The following code might be helpful :
x = 0:0.1:3;
y = -2:0.13:2;
Load = 10;%Integer that we want the elements to replace with
for i = 1:31
if y(i)==0;
x(i)=Load;
end
end
Hope this helps!
Regards,
Pratyush.
2 commentaires
Stephen23
le 10 Fév 2021
"The following code might be helpful "
Even more helpful would be to read this comment from one week ago:
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