Adjusting size of matrix when converting base 10 to binary

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I'm looking to convert a number (0-255) into binary and then put that into a 1x8 matrix returning 1 and 0's. The issue I'm having is fitting the vectors together since a number like 30 gives [1 1 1 1 0] rather than [0 0 0 1 1 1 1 0]. I'd prefer not to manually add in the first rows each time I get to the next 2^n.
Any help is appreciated.
NumBin = num2str(dec2bin(30)) - '0';
%Returns 1 1 1 1 0
NumBin = num2str(dec2bin(255)) - '0';
%Returns 1 1 1 1 1 1 1 1
%Looking for:
% 0 0 0 1 1 1 1 0
% 1 1 1 1 1 1 1 1

Accepted Answer

James Tursa
James Tursa on 16 Feb 2021
Specify the number of binary digits to use. E.g.,
dec2bin(30,8)

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R2019a

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