Variable of one implicit function used in another?

Hi,

I have a function that I am not able to isolate by hand

2.31525+0.231525*sin(2*pi*x)-(1+.2*m.^2).^3/m

where x runs from 0 to 1.

I was able to plot this using fimplicit, but now I want to plot another function that uses these same m values as an input. What is the easiest way to do this?

I am new to matlab and only used one line of code:

fimplicit(@(x,m)2.31525+0.231525*sin(2*pi*x)-(1+.2*m.^2).^3/m,[0 1])

thanks!

[Michael P. Cohen]

to be specific, I am looking to plot:

t = 315/(1+.2m.^2) and p = (1.186/((1+.2m.^2).^-3.5)) each as a function of x

Answer 1

[David Hill]

function out = eqn(x)
  b=@(m)2.31525+0.231525*sin(2*pi*x)-(1+.2*m.^2).^3/m;
  out=fsolve(b,.5);
end


x=0:.01:1;
y=zeros(size(x));
for k=1:length(x)
    y(k)=eqn(x(k));
end
plot(x,y);

[Michael P. Cohen]

Thank you for the answer! This code is still getting an error at the line x=0:.01:1; and I am not sure why

[Walter Roberson]

If you put both in the same file then the function needs to be after the script.

[Michael P. Cohen]

Thanks Walter

[David Hill]

function out = eqn(x)
  b=@(m)2.31525+0.231525*sin(2*pi*x)-(1+.2*m.^2).^3/m;
  out=fsolve(b,.5);
end

Establish function, then run script:

x=0:.01:1;
y=zeros(size(x));
for k=1:length(x)
    y(k)=eqn(x(k));
end
t =@(m) 315./(1+.2*m.^2);
p =@(m) (1.186./((1+.2*m.^2).^-3.5));
subplot(3,1,1);
plot(x,y);
subplot(3,1,2);
plot(x,t(y));
subplot(3,1,3);
plot(x,p(y));