syms with function handler

This is my Matlab code. I am trying to simply substitute the M=[0 0 1] into n like this n1=0 n2=0 n3=1 but the answer comes without the substitution happening. What should I do to fix this?

M=zeros(1,3)

M(1,3) = 1;

syms n [1 5]

f=@(n) n1+6*n2+2*n3

a=f(M)

---------

n =

[ n1, n2, n3]

a =

n1 + 6n2 + 2n3

How can I get

a= 0+0+2

if the substitution happens

Answer 1

[Walter Roberson]

M=zeros(1,3) 

M = 1×3

0 0 0

M(1,3) = 1; 
syms n [1 5]
f = matlabFunction(n1+6*n2+2*n3, 'vars', {n})

f = function_handle with value:
    @(in1)in1(:,1)+in1(:,2).*6.0+in1(:,3).*2.0

a=f(M)

a = 2

[Walter Roberson]

Note: the 'vars', {n} is important there.

M=zeros(1,3) 

M = 1×3

0 0 0

M(1,3) = 1; 
syms n [1 5]
f = matlabFunction(n1+6*n2+2*n3)

f = function_handle with value:
    @(n1,n2,n3)n1+n2.*6.0+n3.*2.0

Notice it created a function that expects three separate input variables instead of a vector of values

a=f(M)

Not enough input arguments.

Error in symengine>@(n1,n2,n3)n1+n2.*6.0+n3.*2.0

[Walter Roberson]

https://www.mathworks.com/matlabcentral/answers/750054-matlab-function-with-multiple-sym-variables?s_tid=srchtitle