Error using movmax index

4 vues (au cours des 30 derniers jours)
david crowley
david crowley le 21 Fév 2021
Commenté : Walter Roberson le 10 Juin 2021
I need to find the number of periods since a stock price recorded an 14-day high. My proposed method was to use the following andpossibly subtract the index from the current row:
n = 14
[M,I] = movmax(high,[n-1 0],'omitnan');
However, I return - "error using movmax. Too many output arguments."
Can someone please assist in my methodology.

Réponses (1)

Walter Roberson
Walter Roberson le 21 Fév 2021
There is no syntax for movmax() in which it returns a second output. It does not return the indices of the local maxima.
  4 commentaires
Raphael Willi
Raphael Willi le 10 Juin 2021
Loop how?
Walter Roberson
Walter Roberson le 10 Juin 2021
wid = 5;
N = 50;
signal = randi([-9, 9], 1, N)
signal = 1×50
-4 -9 -5 8 -6 -2 7 -3 6 -1 5 6 3 -5 -3 -3 -8 0 -8 7 -9 -3 6 0 4 2 -8 -9 3 -3
for K = 1 : N - wid + 1
[M(K), relI] = max(signal(K:K+wid-1));
I(K) = K + relI - 1;
end
M
M = 1×46
8 8 8 8 7 7 7 6 6 6 6 6 3 0 0 7 7 7 7 7 6 6 6 4 4 3 3 3 3 1
I
I = 1×46
4 4 4 4 7 7 7 9 9 12 12 12 13 18 18 20 20 20 20 20 23 23 23 25 25 29 29 29 29 34

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