Help with commands varargin and switch

3 vues (au cours des 30 derniers jours)
NS
NS le 16 Mai 2011
[EDIT: Mon May 16 20:51:23 UTC 2011 - Reformat - MKF]
Hello,
I am new to MATLAB and I am trying to understand the code given in the following paper (Matov et al 'Analysis of microtubule dynamic instability using a plus-end growth marker', Nature, 7, 761-768 (2010).
One of the codes uses command varargin and switch. Could someone please explain the use of these command in MATLAB.
Part of the code is given below %START
function [cutoffIndex, cutoffValue, sp, axesH] = cutFirstHistMode(varargin)
% goodDataIdx is used in case data contains nans
goodDataIdx = [];
% check for axesHandle
if ishandle(varargin{1})
axesH = varargin{1};
varargin(1) = [];
verbose = 1;
else
axesH = [];
end
switch length(varargin) - isscalar(varargin{end})
case 1 % data
doHistogram = 1;
data = varargin{1};
data = data(:);
%END. I have given only a part of this code.
Your help is truly appreciated.
Thanks.

Réponse acceptée

Matt Fig
Matt Fig le 16 Mai 2011
Probably the best thing is for you to read the doc on these topics.
  4 commentaires
NS
NS le 18 Mai 2011
Thanks Jan.
I ran the code. The "if" operator processed the true statements if the argument had a positive value (not 0).
eg. when ishandle(varargin{1})=1 the if statement was processed and when the value was 0 the else statements were processed.
Also I understood what varargin stands for after running the code. Thanks once again
Jan
Jan le 18 Mai 2011
Be careful: "ishandle(varargin{1})=1" is not a comparison, but a standard bug. You want: "ishandle(varargin{1})==1". "if ishandle(varargin{1})" works also, because ISHANDLE replies a LOGICAL already.
"if X" with a numerical X (even an array!) means explicitely: "if all(X) && ~isempty(X)".

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Startup and Shutdown dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by