Spliting a date to day, month and year

Hello,

Suppose I have a date in this form only : 14/2/1923 or 8/2/1923 (not 14/02/1923 or 08/02/1923)

How can I split it to day, month and year? there are no zeros at all in the date.

Thank's!

Answer 1

[José-Luis]

myDate = '4/2/1923';
mySplitDate = regexp(myDate,'/','split');
myDatevec = cellfun(@(x) str2double(x),mySplitDate)

Answer 2

[Andrei Bobrov]

de = {'14/2/1923', '8/2/1923'};

ymd = datevec(de,'dd/mm/yyyy');
out = ymd(:,3:-1:1);

Answer 3

[Jan]

Faster:

S = '14/2/1923';
D = sscanf(S, '%d/%d/%d', 3);

Or for cell strings:

S = {'14/2/1923', '23/12/1924'};
C = sprintf('%s*', S{:});
D = sscanf(C, '%d/%d/%d*', [3, length(S)]);