Elementwise multiplication, function definition

Hello Community
I have an issue defining a function where the input is a meshgrid. Somehow there must be an issue with the elementwise multiplication.
Input: [x, y] = meshgrid(linspace(0,400,400),linspace(0,30000,400));
A1 = -8.269000000000000;
m1 = 2.071000000000000;
m2 = 0.239700000000000;
B1 = -13.100000000000000;
n1 = 2.813000000000000;
B2 = -49.960000000000001;
n2 = 18.170000000000002;
z1 = (10^A1*x.^m1*y.^m2+y.*(10^B1*x.^n1+10^B2*x.^n2))*100;
Output:
min(min(z1)) = 188.7492
Conclusion:
The minimal value of z1 is 188.7492. However looking at the equation, z1 should be 0 for x = 0 and y = 0.
Somehow there is a mistake writing the equation oder defining input (x,y)
Can anybody help me?

 Réponse acceptée

Iman Ansari
Iman Ansari le 17 Mai 2013
[x, y] = meshgrid(linspace(0,400,400),linspace(0,30000,400));
A1 = -8.269000000000000;
m1 = 2.071000000000000;
m2 = 0.239700000000000;
B1 = -13.100000000000000;
n1 = 2.813000000000000;
B2 = -49.960000000000001;
n2 = 18.170000000000002;
z1 = (10^A1*x.^m1.*y.^m2+y.*(10^B1*x.^n1+10^B2*x.^n2))*100;
min(min(z1))

1 commentaire

Ben
Ben le 17 Mai 2013
Thank you! You must be a wizard! Have a nice day!

Connectez-vous pour commenter.

Plus de réponses (1)

Hi, try your code like this:
[x, y] = meshgrid( linspace(0,400,400),linspace(0,30000,400) );
A1 = -8.269000000000000;
m1 = 2.071000000000000;
m2 = 0.239700000000000;
B1 = -13.100000000000000;
n1 = 2.813000000000000;
B2 = -49.960000000000001;
n2 = 18.170000000000002;
AA = 10^A1;
BB = x.^m1;
CC = y.^m2;
z1_1 = AA.*BB.*CC;
DD = 10^B1;
EE = x.^n1;
FF = 10^B2;
GG = x.^n2;
z1_2 = y.*( DD*EE + FF*GG );
z1 = ( z1_1 + z1_2 )*100;

2 commentaires

You will get you zero values along with values close to 0 too.
Ben
Ben le 17 Mai 2013
Thank you for spending time on my problem! The solution above works very fine an was what I was going for. Have a nice day!

Connectez-vous pour commenter.

Catégories

En savoir plus sur Graphics Performance dans Centre d'aide et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by