getting "Index exceeds matrix dimensions." Can anyone explain?
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function [ coordinates ] = readSTL1( filename,k)
% reads ASCII STL file and gives coordinates of vertices.
%filename-name of file(test.txt),k- number of rows in cell.
fid=fopen(filename);
C=textscan(fid,'%s');
%reads file and generates cell.
m = 11;
i = 1;
coordinates = zeros(4455,1);
while(m < (k-3))
j = 1;
while (j < 4)
l = 1;
while(l<4)
coordinates(i) = C(m);
l = l+1; % makes sure loop runs thrice.
m = m+1; % access corresponding row from cell'C'.
i = i+1; % row number in output matrix.
end
m = m+1;
j = j+1;
end
m = m+10;
end
end
Réponses (2)
Walter Roberson
le 21 Mai 2013
Are you sure that is your code? textscan() returns a cell array, so your C is a cell array and thus C(m) is a 1x1 cell array (which has a string inside it), but you cannot assign a cell array into a numeric array (you initialized coordinates as zeros() which is numeric).
Even if you were to change it to C{m} then C{m} would be a string, most likely of multiple characters, and assigning multiple characters into a single numeric location is not going to work.
When you use textscan with a '%s' format, the input will be divided up into (whitespace delimited) strings with line boundaries treated the same as whitespace, so C will contain one location per string. e.g.,
fizz 19 39
bar
would return
{'fizz'; '19'; '39'; 'bar'}
You assume in your code that m starts from 11, so your code that accesses C(m) is going to fail of there were not at least 11 strings in the file.
2 commentaires
Walter Roberson
le 21 Mai 2013
At the command line, give the command
dbstop if error
then run the program. When it stops at the error you indicated, examine size(C) and the value of m .
Iain
le 21 Mai 2013
If you know the indices of where the data is, you can instead do:
Indices = [ 11 12 13 15 16 17 19 20 21 32 33 34 36 37 38 40 41 42];
for i = 1:numel(Indices)
coordinates(i) = C{Indices(i)};
end
The error occurs because your "m" is larger than the number of elements in C.
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