saving a matrix of each loop

HELLO! i am trying to save a matrix on each loop.

i know this is simple syntax but it is not working for me. This is the code i have where i know there is a syntax error. it just keeps overriding the previous matrix.

while(fin)
        % made seperate matrix for the test 
        for i=1:length(pts)
            matrix = [x(next:pts(i,:)), y(next:pts(i,:)), test(next:pts(i,:))];
            next = pts(i);
        end
        if pts(i) == length(pts)
            fin = 0;
        end
       
        return 
end 

i then attempted to add this, and this is the error coming up.

test(i,:) = matrix;

Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.

i have attempted to use matrix{i} but that gives me a cell and i cant handle it the way i want to. none of the cell commands work...

i have also tried matrix(:,i) = [x(next:pts(i,:)), y(next:pts(i,:)), test(next:pts(i,:))];

Unable to perform assignment because the indices on the left side are not compatible with

the size of the right side.

Error in arrayplay (line 56)

matrix(:,i) = [x(next:pts(i,:)), y(next:pts(i,:)), num_step(next:pts(i,:))];

please help. im just about ready to cry.

Answer 1

[KSSV]

You can save them into a cell as shown below.

iwant = cell([],1) ;  % initilize a cell array; 
while(fin)
        % made seperate matrix for the test 
        for i=1:length(pts)
            matrix = [x(next:pts(i,:)), y(next:pts(i,:)), test(next:pts(i,:))];
            next = pts(i);
            iwant{i} = matrix ;   % save into a cell 
        end
        if pts(i) == length(pts)
            fin = 0;
        end
       
        return 
end 

Access the cell using: iwant{1}, iwant{2},...etc.

You can also initialize it into amatrix, if dimensions are known in prior and if dimensions don't change in a loop.

[caroline bourn]

thanks! so the next step is writing a code that will go through the contents of each cell and do whatever to it. is there a way to do it simply?

[KSSV]

If the dimensions remains same, you can save them into a matrix or you can also convert cell array into matrix using Cell2mat.

[caroline bourn]

the dimensions are not the same :( is there a better way?

[KSSV]

Then go by cell array....if problem is well known there might be another easy way.

[caroline bourn]

im sorry, i don't understand. could you explain it a bit further?