How can I vectorize this code?

i had a loop:
for j=1:length(Pa)
for i=1:(length(r)-1)
Ip=2*Pa(j)*exp(-2*r(i)^2/wa^2)/(pi*wa^2); % Интенсивность накачки, Вт/м^2
Is=2*Pin*exp(-2*r(i)^2/wa^2)/(pi*wl^2); % Интенсивность сигнала, Вт/м^2
a=Is/Issat;
b=Ip/Ipsat;
zspan=[0 l];
startval=[b; a];
[z1,y1]=ode23(@(z,y) famplifire(sigma_pa,N0,sigma_pe,sigma_se,k,y,z),zspan,startval);
xrx=y1;
itog=itog+y1(end,2)*(r(i+1)^2-r(i)^2)/2;
%tt(i)=y1(end,2)
%rer=sum(tt,'all')
end
qwwer(1,j)=itog*2*pi*Issat;
itog=0;
end
I tryed to transform the first loop on j into something like j=1:1:length(Pa). But I had a problem. Variable startval is a variable that contain initial values for the solver of differential equation. When I change my loop to the vector, no matter either i do this for i or j, I obtain vector b(1,26) or even two vectors a(1,26) and b(1,26). As far as I know, startval should contain only (1,1) vectors or just numbers (also matlab writes that there are wrong dimension of startval if I try to make vectorization). So I need to write another loop specially for a and b. Something like:
for j=1:length(Pa)
startval=[b[j] a];
[z1,y1]=ode23(@(z,y) famplifire(sigma_pa,N0,sigma_pe,sigma_se,k,y,z),zspan,startval);
end
I don't want to do this, because I think that shouldn't make my code work faster.
So, can you told me, can I use vectorization here and how I can do that?

1 commentaire

Rik
Rik le 11 Mar 2021
startval=[b[j] a];
This is not valid Matlab syntax. It is also unclear to me what it attempt to do.
If you want to run ode23 over a grid of values, there might not actually be a shortcut.

Connectez-vous pour commenter.

Réponses (1)

Walter Roberson
Walter Roberson le 11 Mar 2021
Modifié(e) : Walter Roberson le 22 Avr 2021

1 vote

Modify famplifire so that it accepts a vector of y values, and reshapes the values to 2 columns, and then computes values for each row. For example, convert
function dy = famplifier(z, y)
dy = [-y(2); sin(y(1)) + cos(y(2))];
end
into
function dy = famplifier(z, y)
y = reshape(y, [], 2);
y1 = y(:,1);
y2 = y(:,2);
dy = [-y2, sin(y1) + cos(y2)];
dy = dy(:);
end
Now create startval as an array with two columns of the boundary conditions
Ip = 2*Pa(:).*exp(-2*r.^2./wa.^2)./(pi.*wa.^2); % Интенсивность накачки, Вт/м^2
Is = 2*Pin.*exp(-2*r.^2./wa.^2./(pi.*wl.^2); % Интенсивность сигнала, Вт/м^2
a = Is/Issat;
b = Ip/Ipsat;
startval = [b(:), a(:)];
[z1,yout]=ode23(@(z,y) famplifire(sigma_pa,N0,sigma_pe,sigma_se,k,y,z),zspan,startval);
yout will then be a 2D array that you can
yout2 = reshape(yout, size(yout,1), [], 2);
First pane, yout2(:,:,1) corresponds to the old y1(:,1), second pain yout2(:,:,2) corresponds to the old y1(:,2), with the rows corresponding to time, the columns corresponding to the different b and a value pairs.

9 commentaires

George Bashkatov
George Bashkatov le 18 Avr 2021
Modifié(e) : George Bashkatov le 18 Avr 2021
Matlab writes that error in line
startval = [b(:), a(:)];
Dimensions of arrays being concatenated are not consistent.
In workspace I see, that a is a 1x10001 double and b is a 26x10001 double
Walter Roberson
Walter Roberson le 18 Avr 2021
Ah, I see why that would happen, but it will take me some thinking on how best to fix it.
Ip = 2*Pa(:).*exp(-2*r.^2./wa.^2)./(pi.*wa.^2); % Интенсивность накачки, Вт/м^2
Is = repmat(2*Pin.*exp(-2*r.^2./wa.^2./(pi.*wl.^2)), length(Pa), 1); % Интенсивность сигнала, Вт/м^2
a = Is/Issat;
b = Ip/Ipsat;
startval = [b(:), a(:)];
Thank you for your help, but the code doesn't work((
1) You forget to write
zspan=[0 l];
before
[z1,yout]=ode23(@(z,y) famplifire(sigma_pa,N0,sigma_pe,sigma_se,k,y,z),zspan,startval);
2) We vectorize the startval.My first code gives one value during each iterration. So, after the code to be executed it gives me two values: [0.0029;0.0015]. After vectorization my code gives me an array 260026x2. And the last values in each column should coincide with [0.0029;0.0015]. I see, that the value in the first column coincide with 0.0029, but the second is not. And I don't know how to fix that.
Because of this problem, my programs works infinitely without any result. Maybe the code has another problems too, but I can't analyse them by reason of startval.
Walter Roberson
Walter Roberson le 20 Avr 2021
I cannot test as you did not post your input values.
sigma_pa=0.6*10^(-18)*10^(-4);
sigma_pe=0.3*10^(-18)*10^(-4);
sigma_se=0.9*10^(-18)*10^(-4);
lambda_s=2.5*10^(-6);
lambda_p=1.9*10^(-6);
c=2.99792458*10^8;
Vp=c/lambda_p;
Vs=c/lambda_s;
h=6.626*10^(-34);
tau=4*10^(-6);
wa=80*10^(-6);
wl=80*10^(-6);
N0=1*10^19*10^6;
l=7.8*10^-3;
k=N0*sigma_pa/(sigma_pa+sigma_pe);
Pin=10;
Pa=(0:1:25);
Issat=(h*Vs)/(sigma_se*tau);
Ipsat=(h*Vp)/((sigma_pa+sigma_pe)*tau);
step=2*wa/10000
r=(0:step:2*wa);
itog=0;
After all calculations I need to obtain qwwer (in the first code variant you can see how it can be calculated) and plot it by the command:
plot(Pa,qwwer);
You have
[z1,yout]=ode23(@(z,y) famplifire(sigma_pa,N0,sigma_pe,sigma_se,k,y,z),zspan,startval);
which passes 7 parameters to famplifire but that function only expects two parameters ?
Also please post your revised code to calculate qweer now that you are no longer looping the ode23 call.
1)The old function looks like (before vectorization):
function dydz = famplifire(sigma_pa,N0,sigma_pe,sigma_se,k,y,z)
k=N0*sigma_pa/(sigma_pa+sigma_pe);
dy1 = y(1).*(-sigma_pa.*N0+(sigma_pa+sigma_pe).*(k.*y(1)./(y(1)+y(2)+1)));
dy2 = y(2).*sigma_se.*(k.*y(1)./(y(1)+y(2)+1));
dydz = [dy1; dy2];
after:
function dydz = famplifire11(sigma_pa,N0,sigma_pe,sigma_se,k,y,z)
y = reshape(y, [], 2);
k=N0*sigma_pa/(sigma_pa+sigma_pe);
dy1 = y(:,1).*(-sigma_pa.*N0+(sigma_pa+sigma_pe).*(k.*y(:,1)./(y(:,1)+y(:,2)+1)));
dy2 = y(:,2).*sigma_se.*(k.*y(:,1)./(y(:,1)+y(:,2)+1));
dydz = reshape([dy1, dy2],[],1);
the function expects 7 parameters.
2) So, the revised code.
clear, close all;
sigma_pa=0.6*10^(-18)*10^(-4);
sigma_pe=0.3*10^(-18)*10^(-4);
sigma_se=0.9*10^(-18)*10^(-4);
lambda_s=2.5*10^(-6);
lambda_p=1.9*10^(-6);
c=2.99792458*10^8;
Vp=c/lambda_p;
Vs=c/lambda_s;
h=6.626*10^(-34);
tau=4*10^(-6);
wa=80*10^(-6);
wl=80*10^(-6);
N0=1*10^19*10^6;
l=7.8*10^-3;
k=N0*sigma_pa/(sigma_pa+sigma_pe);
Pin=10;
Pa=(0:1:25);
Issat=(h*Vs)/(sigma_se*tau);
Ipsat=(h*Vp)/((sigma_pa+sigma_pe)*tau);
step=2*wa/10000;
r=0:step:2*wa;
itog=0;
j=1:length(Pa);
for i=1:(length(r)-1)
Ip = 2*Pa(:).*exp(-2*r.^2./wa.^2)./(pi.*wa.^2);
Is = repmat(2*Pin.*exp(-2*r.^2./wa.^2./(pi.*wl.^2)), length(Pa), 1);
a = Is/Issat;
b = Ip/Ipsat;
zspan=[0 1];
startval = [b(:), a(:)];
[z1,yout]=ode23(@(z,y) famplifire11(sigma_pa,N0,sigma_pe,sigma_se,k,y,z),zspan,startval);
yout2 = reshape(yout, size(yout,1), [], 2);
xrx=yout2;
itog=itog+yout2(end,:,2)*(r(i+1)^2-r(i)^2)/2;
end
qwwer(1,j)=itog*2*pi*Issat;
hold on
plot(Pa,qwwer);
xlabel('Мощность накачки, Вт')
ylabel('Выходная мощность генерации, Вт')
grid on
George Bashkatov
George Bashkatov le 5 Mai 2021
There is no ideas anymore?(

Connectez-vous pour commenter.

Catégories

En savoir plus sur MATLAB dans Centre d'aide et File Exchange

Produits

Version

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by