output will not suppress even with a semi colon

Hello I am having an issue with a code. I have a semi colon everywhere in my code yet it still outputs the answer when I don't want it to. I have the code below. It will always outputs j and I have no idea how to make it stop. Any help would be appreciated! Thank you in advance.

[ j, out, Matches ] = Make_Numbers(Test_Sum, DATA, Thold, Bonusflag, n)

out = DATA;

[a,b] = size(DATA);

out = [out cellstr(num2str((1:a)'))];

start = 1;

stop = a;

e = 1;    

for i = 1:e;

      Test_Sum = max(Test_Sum, Test_Sum');

      [~,Matches] = find_matches(Test_Sum,Thold);

      sub_Graph = find_subgraph(Matches);

      disp(num2str(length(sub_Graph)));

      %Strength Function

      if(Bonusflag)

          STR = strength(sub_Graph, Test_Sum);
          [sub_Graph,peoplenum] = refineID(STR,DATA(start:stop,35), AAA, 
  sub_Graph);

          disp([num2str(peoplenum) ' members']);

      end

      [c,~] = size(Test_Sum);
      temp = cell(c,1);
      [~,d] = size(sub_Graph);
      check = true(d,1);

      for j = 1:d;
          target = sub_Graph{1,j};
          [~,h] = size(target);
          for k = 1:h;
              temp{target(1,k), 1} = ([num2str(n,'%02d') '-' num2str(j,'%04d')]);
              check(target(1,k),1) = false(1,1);
          end
      end

      if(sum(check))
          error('NOT ALL PERSONS USED');
      end

      out(start:stop, b+1) = temp;
  end
  end

Answer 1

[Roger Stafford]

Semicolons will not suppress the actions of the 'disp' function. You need to remove them if you don't want to see an output from them.

Also I notice you don't have a semicolon after the first line and the "function" designation is not there. That will produce an output as it stands.

[Ryan]

Wow, thank you so much. I just commented out the disp and it worked. Thank you.