# Detect the error position in a vector and correct it (Matlab)

2 vues (au cours des 30 derniers jours)
Afluo Raoual le 18 Mar 2021
Commenté : Afluo Raoual le 18 Mar 2021
Dear members;
I have the code word C of length 'M' and I have also the received vector V after decoding of the same length 'M' as C
For example:
V=[1 0 0 1 0 1 0 1 0 0]
C=[1 1 0 1 0 0 0 1 0 0]
I want firstly detecting the position of each bold bit of V and than correct it by adding 1 to those bits (because in mod2: 0+1=1 and 1+1=0) in order to obtain V=C
How can I do that please
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Adam Danz le 18 Mar 2021
> I want firstly detecting the position of each bold bit of V
Ah, so what you really want to do is find the index of the vector where V(i) is not equal to C(i).
Afluo Raoual le 18 Mar 2021
Exactly yes, and then correct the bold bits of V in order to obtain them equal to C

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### Réponse acceptée

Christopher McCausland le 18 Mar 2021
Hi Afluo,
You can try something like the below to assess where the diffrences between the arrays are; after this just cycle to these locations and change the value as you need.
I hope this helps,
Christopher
V=[1 0 0 1 0 1 0 1 0 0]
C=[1 1 0 1 0 0 0 1 0 0]
diff_Check = V ~= C;
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Adam Danz le 18 Mar 2021
Modifié(e) : Adam Danz le 18 Mar 2021
I agree with Christopher McCausland , this does describe what you want to do but is missing the final step which is quite straightforward and something you could fill in yourself,
V=[1 0 0 1 0 1 0 1 0 0];
C=[1 1 0 1 0 0 0 1 0 0];
V(V~=C) = V(V~=C) + 1;
mod(V,2)
ans = 1×10
1 1 0 1 0 0 0 1 0 0
Afluo Raoual le 18 Mar 2021
Thank you so much. It works

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