Get Windows taskbar height
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Hello! I can't get the correct Windows taskbar height by code. I need it for the define the height of my app (app design).
I get the right value only with the following, but I don't like the need to create an empty figure just for the purpose, it is not neat:
h = figure('Menu','none','ToolBar','none','WindowState','maximized','Visible','on');
pause(1)
P2 = get(h,'Position');
P2(2)
close(h);
ans =
41 % correct value! Perfect result using this
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/561303/image.png)
Moreover, the previous does not work setting Visible = 'off', it does not update the maximized sizes.
I read this : Finding the height of windows taskbar - MATLAB Answers - MATLAB Central (mathworks.com)
but it does not work:
toolkit = java.awt.Toolkit.getDefaultToolkit();
scr_size = toolkit.getScreenSize();
fprintf('Screen size is: %d x %d\n', scr_size.width, scr_size.height)
jframe = javax.swing.JFrame;
insets = toolkit.getScreenInsets(jframe.getGraphicsConfiguration());
fprintf('Windows task bar height is: %d\n', insets.bottom)
>>>> Screen size is: 2880 x 1620
>>>> Windows task bar height is: 60 % WRONG
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/561308/image.png)
what can I do? Thank you
For the app size, I use:
screenSize = get(groot,'ScreenSize');
screenWidth = screenSize(3);
screenHeight = screenSize(4);
left = screenWidth;
bottom = P2(2);
width = screenWidth*0.20;
height = (screenHeight-P2(2))*0.97;
drawnow;
app.MyApp.Position = [left bottom width height];
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Réponse acceptée
Jan
le 24 Mar 2021
You can move the taskbar to the side and to the top, hide it dynamically and change the size. The static determination of the height is not reliable.
You can use FEX: WindowAPI to determine the sizes of the monitors with and without task bar. The the problem remains the same: If the taskbar is dynamically faded or moved, the GUI has to be adjusted.
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